Question

A ball is projected vertically upwards with an initial velocity of 50 m/s.Calculated velocity after 2s?

Answer 1

• 30.4 m/s

Step-by-step explanation:

When a ball is projected vertically upwards, the acceleration due to gravity ( g ) acts downwards and since is acts opposite to the direction of motion it will thus deaccelerate the ball .

If we consider upwards direction positive, then the direction of g will be -ve . Value of g is approximately 9.8 m/s² .

We need to find the velocity after 2s . So for that we can use first equation of motion ;

`\implies v = u + at \\\\`

where the symbols have their usual meanings.

On substituting the respective values we have,

`\implies v = \{ 50 - 9.8(2)\} \ m/s \\\\`

`\implies v = ( 50 - 19.6 ) \ m/s\\\\`

`\implies \boxed{ v = 30.4 \ m/s }\\\\`

Hence the velocity of ball after 2s is 30.4 m/s .