Final answer:
The correct explanation is option A. Melting ice releases energy (ΔH<0), and ΔS<0 because the motion of the H₂O molecules decreases as it transitions from solid to liquid.
Step-by-step explanation:
The correct answer is option A. Melting ice releases energy (ΔH<0), and ΔS<0 because the motion of the H₂O molecules decreases as it transitions from solid to liquid. At a temperature higher than 0 degrees Celsius, the term TΔS is smaller than ΔH, resulting in a thermodynamically favorable process with ΔG<0.
Enthalpy (ΔH) is the heat energy absorbed or released during a process, and entropy (ΔS) is a measure of the disorder or randomness of a system. Gibbs free energy (ΔG) represents the balance between enthalpy and entropy in a system.
In this case, melting ice is an exothermic process, meaning it releases energy (ΔH<0). The transition from solid to liquid results in a decrease in the motion of the H₂O molecules, leading to a decrease in entropy (ΔS<0).
However, at a temperature higher than 0 degrees Celsius, the term TΔS (where T is temperature) is smaller than ΔH. This means that the increase in enthalpy is greater than the decrease in entropy, resulting in a negative value for Gibbs free energy (ΔG<0). A negative value for ΔG indicates that the process is thermodynamically favorable.