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A cool water sample absorbed 3,135 J of energy from hot metal. The temperature of the 63.0 g piece of metal changed from 382°C to 20.0°C. What is the specific heat of the metal? Cₘₑₜₐₗ=[?] J/g·°C

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Final answer:

The specific heat of the metal is calculated as 0.138 J/g°C using the formula q = m × c × ΔT, where q is the heat absorbed, m is the mass of the metal, c is the specific heat capacity, and ΔT is the change in temperature.

Step-by-step explanation:

To calculate the specific heat of the metal, we use the formula:
q = m × c × ΔT, where q is the heat absorbed or released (3,135 J), m is the mass of the metal (63.0 g), c is the specific heat capacity, and ΔT is the change in temperature. Since we know the initial and final temperatures of the metal, we can find ΔT as 382°C - 20.0°C = 362°C.

Using the given values, we rearrange the formula to solve for c:
c = q / (m × ΔT)

Substituting the numbers in:
c = 3,135 J / (63.0 g × 362°C)

After calculating, we get the specific heat of the metal as c = 0.138 J/g°C.

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