Question

there is an 18 pound bag of cat food and the cat eats 0.5lbs a day what is the first term of this sequence

Answer 1

The first term of the sequence is the original weight of the 18-pound bag of cat food. To calculate the percent uncertainty of a 5.1-pound bag of apples with ±0.3-pound uncertainty, we divide the uncertainty by the average weight and then multiply by 100, resulting in approximately 5.88%.

Step-by-step explanation:

To answer the question related to the weight of a bag of cat food and the percent uncertainty of a bag's weight, let us first clarify the question about the cat food. The student has an 18-pound bag of cat food, and the cat eats 0.5 pounds per day. The first term in this sequence refers to the weight of the cat food on the first day, which is simply the original weight of the bag.

Now, regarding the question of finding the percent uncertainty, the student provides the information that the average weight of a 5-pound bag of apples is determined to be 5.1 pounds, with an uncertainty of ±0.3 pounds. The percent uncertainty is a measure of how precise this measurement is and is calculated as the ratio of the uncertainty to the measured value, times 100 to express it as a percentage.

Here's the calculation for the percent uncertainty:

1. First, we take the stated uncertainty, which is 0.3 pounds.
2. Then we divide this by the average weight. In this case, 0.3 pounds ÷ 5.1 pounds.
3. Finally, we multiply the result by 100 to convert it to a percentage.

Percent uncertainty = ±0.3 pounds ÷ 5.1 pounds × 100

Performing this calculation:

Percent uncertainty = (0.3 ÷ 5.1) × 100 ≈ 5.88%

The percent uncertainty of the bag's weight is approximately 5.88%.