Question

An antacid tablet was dissolved in 26.00 mL of 0.650 M HCl. The excess acid was back-titrated with exactly 11.44 ml of 1.05 M NaOH. The average weight of a tablet is 0.834 g. The tablet came from a bottle of 150 tablets that

Calculate the moles of HCl neutralized by the tablet.

Answer 1

To calculate the moles of HCl neutralized by the antacid tablet, we need to determine the moles of NaOH used in the titration and conclude that the same amount of moles of HCl were neutralized.

Step-by-step explanation:

To calculate the moles of HCl neutralized by the antacid tablet, we can use the equation of the neutralization reaction:

HCl + NaOH → NaCl + H2O

From the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NaOH.

To find the moles of HCl neutralized, we need to determine the moles of NaOH used in the titration. We can calculate the moles of NaOH using the following formula:

moles of NaOH = (volume of NaOH)(molarity of NaOH)

Once we have the moles of NaOH, we can conclude that the same amount of moles of HCl were neutralized by the antacid tablet. Therefore, the moles of HCl neutralized is equal to the moles of NaOH used in the titration.