Final answer:
To calculate the resulting nitrate ion concentration, the total moles of nitrate ions from both potassium nitrate and calcium nitrate are summed up and then divided by the total volume of the mixture, resulting in a concentration of 2.325 M.
Step-by-step explanation:
To determine the resulting nitrate ion concentration when 95.0 mL of 0.992 M potassium nitrate and 155.5 mL of 1.570 M calcium nitrate are combined, we must use the concept of molarity and volume to calculate the total number of moles of the nitrate ion and then use the total volume for the concentration calculation.
The number of moles of nitrate ions from potassium nitrate is given by multiplying the molarity (0.992 M) by the volume (0.095 L), which equals 0.09424 moles. The number of moles of nitrate ions from calcium nitrate is twice the product of its molarity (1.570 M) and volume (0.1555 L) as there are two nitrate ions per formula unit of calcium nitrate, yielding 0.48741 moles.
The total moles of nitrate ions is the sum of both, which is 0.09424 + 0.48741 = 0.58165 moles. Lastly, the total volume in which the nitrate ions are dissolved is the sum of both solution volumes, which is 0.095 L + 0.1555 L = 0.2505 L. Hence, the nitrate ion concentration is calculated by dividing the total moles of nitrate ions by the total volume: 0.58165 moles / 0.2505 L = 2.325 M, which is the resulting concentration of nitrate ions in the mixture.