Question

In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constructed. Ignoring Earth's rotation, find the change in your weight if you were to ride an elevator from the street level, where you weigh 700 N, to the top of the building.

What I did:
radius of earth = r = 6.38x10⁶m
mass of earth = M = 5.97x10²⁴ kg
mass of person = m = 700N/9.81 = 71.36kg
height of building = h = 1609.34 m
G = 6.67⁻¹¹

F = mg(top of building) = (G*m*M)/(r + h)² = 697.741 N
mg(top of building)- mg(ground) = 697.741N

Answer 1

The difference in gravitational force at the top of the mile-high building compared to street level can be calculated using the formula for gravitational force, taking into account the height of the building and the initial weight of the person.

Step-by-step explanation:

The question involves calculating the change in weight of a person if they were to ride an elevator from street level to the top of a proposed mile-high building in Chicago by Frank Lloyd Wright, ignoring Earth's rotation.

Given that the person weighs 700 N at street level, we can use the formula for gravitational force to calculate their weight at the top of the building. The formula for gravitational force is F = (G * m * M) / r^2, where F is the gravitational force or weight, G is the gravitational constant, m is the mass of the object (in this case, the person), M is the mass of the Earth, and r is the distance from the center of the Earth to the object.