Question

OAO Trading sold 50 toys. One brand sold at Php40.00 each and another sold at Php60.00 each. Altogether, Php2 300.00 was earned from both brands. How many of each brand was sold?

a. Define one variable for the less expensive brand of toy. Define a second variable for the more expensive brand of toy.

Answer 1

The solution is 35 toys sold at Php40.00 each and 15 toys sold at Php60.00 each.

Step-by-step explanation:

To solve this problem, we need to define two variables. Let's define x as the number of toys sold at Php40.00 each, and y as the number of toys sold at Php60.00 each.

We know that the total number of toys sold is 50, so we can write the equation x + y = 50.

We also know that the total earnings from both brands is Php2,300.00, so we can write the equation 40x + 60y = 2,300.

Now we have a system of linear equations. We can solve this system using any method, such as substitution or elimination, to find the values of x and y.

Let's solve this using substitution:

1. From equation 1, we can write x = 50 - y.
2. Substitute the value of x in equation 2: 40(50 - y) + 60y = 2,300.
3. Simplify the equation: 2,000 - 40y + 60y = 2,300.
4. Combine like terms: 20y = 300.
5. Divide both sides by 20: y = 15.
6. Substitute the value of y in equation 1: x = 50 - 15.
7. Simplify the equation: x = 35.

Therefore, 35 toys were sold at Php40.00 each, and 15 toys were sold at Php60.00 each.