Question

a 10.0ml vinegar sample was completely neutralized by 22.5 ml 0.2 m naoh solution. calculate the molarity and % of acetic acid in vinegar

Answer 1

To calculate the molarity of acetic acid in vinegar, we use the equation (Molarity of acid) * (Volume of acid) = (Molarity of base) * (Volume of base). The molarity of acetic acid in vinegar is 0.45 M, and the percentage of acetic acid in vinegar is 4.5%.

Step-by-step explanation:

To calculate the molarity of acetic acid in vinegar, we can use the equation:

(Molarity of acid) * (Volume of acid) = (Molarity of base) * (Volume of base)

Plugging in the given values:

(Unknown Molarity) * (10.0 mL) = (0.2 M) * (22.5 mL)

Solving for the unknown molarity:

(Unknown Molarity) = (0.2 M * 22.5 mL) / 10.0 mL

(Unknown Molarity) = 0.45 M

To calculate the percentage of acetic acid in vinegar:

Percentage = (Molarity of acid / Total volume) * 100%

Plugging in the values:

Percentage = (0.45 M / 10.0 mL) * 100%

Percentage = 4.5%