Question

When light originates from a point 25 cm to the left of a diverging lens, it comes out the other side with completely parallel rays. Using this lens, you would like to create a virtual, upright image that is 1/6 the size of the object. Where should the object be placed?

A. 60 cm
B. 100 cm
C. 90 cm
D. 125 cm

Answer 1

To create a virtual, upright image that is 1/6 the size of the object using a diverging lens, the object should be placed 60 cm from the lens.The correct option is option a.

Step-by-step explanation:

In order to create a virtual, upright image that is 1/6 the size of the object using a diverging lens, the object should be placed 60 cm from the lens.

When light originates from a point 25 cm to the left of a diverging lens, it comes out the other side with completely parallel rays. This means that the image will be formed at the same distance from the lens as the object, but on the same side as the object.

The magnification of the lens is given by the equation magnification = -image distance / object distance. Since we want the image to be 1/6 the size of the object, the magnification will be -1/6. Plugging in the values, we can solve for the image distance to be 60 cm.