Question

Water travels through a pipe at 11.1 m/s. The pipe contracts from a cross sectional area of 2.3 m² to an area of 0.329 m². what is the speed of the water in the second part of the pipe in m/s?

_______m/s
tries 0/2

Answer 1

To find the speed of water in the second part of the pipe, we can use the principle of continuity. Using the equation A1V1 = A2V2 and plugging in the given values, we find that the speed of the water in the second part of the pipe is 77.674 m/s.

Step-by-step explanation:

To find the speed of water in the second part of the pipe, we can use the principle of continuity, which states that the mass flow rate of a fluid is constant in a pipe. In this case, we can use the equation:

A1V1 = A2V2

Where A1 and A2 are the cross-sectional areas of the pipe at the first and second parts respectively, and V1 and V2 are the velocities of the water at the first and second parts respectively.

Plugging in the given values:

(2.3 m²)(11.1 m/s) = (0.329 m²)(V2)

Solving for V2, we get:

V2 = (2.3 m²)(11.1 m/s) / (0.329 m²) = 77.674 m/s

Therefore, the speed of the water in the second part of the pipe is 77.674 m/s.