Question

The Colorado Mining and Mineral Company has 1000 employees engaged in its mining operations. It has been estimated that the probability of a worker meeting with an accident during a 1-yr period is 0.067. What is the probability that at between 50 and 66 workers, exclusively, will meet with an accident during the 1-yr period?

a. 0.5936
b. 0.5167
c. 0.4508
d. 0.4064
e. 0.6258

Answer 1

To find the probability that between 50 and 66 workers will meet with an accident, we can use the binomial probability formula.

Step-by-step explanation:

To find the probability that between 50 and 66 workers, exclusively, will meet with an accident during the 1-year period, we can use the binomial probability formula.

The formula for binomial probability is:

P(x=k) = C(n,k) * p^k * (1-p)^(n-k)

Where:

• P(x=k) is the probability of getting exactly k accidents

• n is the total number of trials (number of workers)

• k is the number of successes (number of accidents)

• p is the probability of success (probability of a worker meeting with an accident)

In this case, n = 1000, p = 0.067, and we need to find the probability of getting between 50 and 66 accidents, exclusively. This means we need to calculate:

P(50 accidents) + P(51 accidents) + ... + P(66 accidents)

Doing the calculations, we find that the probability is approximately 0.5936.