Final answer:
To create a 0.1 M solution from a 0.60 M copper(II) sulfate stock solution, dilute 16.67 mL of the stock solution to a total volume of 100 mL with distilled water.
Step-by-step explanation:
The question asks about the dilution of a copper(II) sulfate solution to achieve a different molarity. To find the volume needed to be added to dilute a 0.60 M solution to a 0.1 M solution with a total final volume of 100 mL, we can use the formula C1V1 = C2V2 where C1 is the initial concentration, V1 is the volume of the initial concentrated solution, C2 is the final concentration, and V2 is the final volume of the diluted solution.
By rearranging the formula to solve for V1, we get V1 = (C2V2) / C1. Substituting the given values into the equation gives us V1 = (0.1 M × 100 mL) / 0.60 M = 10/0.6 = 16.67 mL. So, you would need to add 16.67 mL of the 0.60 M copper(II) sulfate solution to the flask, and then add distilled water until the total volume is 100 mL to achieve a 0.1 M solution.