Final answer:
Yes, it's possible to have the specified number of instructions within an 11-bit instruction format. The format can support 5 two-address instructions, 45 one-address instructions, and 32 zero-address instructions because the opcode and address fields fit within the 11-bit length.
Step-by-step explanation:
To determine if it's possible to have 5 two-address instructions, 45 one-address instructions, and 32 zero-address instructions within an 11-bit instruction format with a 4-bit address field, we need to analyze the instruction format more closely.
An instruction is typically broken down into an opcode field and address field(s). The opcode field indicates the type of operation to be performed, and the address field(s) indicate the operand(s).
- Two-address instructions require two address fields. Hence, two 4-bit address fields amount to 8 bits, leaving 3 bits for the opcode field. With 3 bits, you can have a maximum of 2^3 = 8 different opcodes. Therefore, having 5 two-address instructions is possible since it requires 5 unique opcodes from the available 8.
- One-address instructions have one 4-bit address field, which leaves 7 bits for the opcode field. With 7 bits for opcodes, you can have up to 2^7 = 128 different opcodes. So, it is possible to have 45 one-address instructions.
- Zero-address instructions don't require address fields, leaving all 11 bits for the opcode. Therefore, you can have 2^11 = 2048 different opcodes. Thus, it is possible to have 32 zero-address instructions.
In conclusion, yes, it's possible to have 5 two-address instructions, 45 one-address instructions, and 32 zero-address instructions using the specified 11-bit instruction format.