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Emma invested $630 in an account in the year 1997, and the value has been growing exponentially at a constant rate. The value of the account reached $840 in the year 2002. Determine the value of the account, to the nearest dollar, in the year 2005.​

User Scabbage
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2 Answers

24 votes
24 votes

Answer:

$966

Explanation:

Given that $630 was invested in 1997

At a constant rate the value grew to $840 in 2002.

This implies that $210 was gotten in 5years:

$(840-630)=$210

and 2002-1997= 5years

therefore, to determine the value of the account in 2005: 2005-1997=8years

$210=5years

$x=8years

CROSS MULTIPLY

5x= 210×8

5x=1680

x=$336

Value of account in 2005 will be: $630+$336=$966

Therefore $966 was made in the next 8years(2005).

User Swarmp
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18 votes
18 votes
Refer down below ………
Emma invested $630 in an account in the year 1997, and the value has been growing-example-1
User Jobajuba
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