Final answer:
The final velocity of an object falling from a height of 39.6 meters, ignoring air resistance, is approximately 27.9 m/s, calculated using the formula v = \(\sqrt{2gh}\) with g = 9.81 m/s2.
Step-by-step explanation:
The student is asking about the final velocity of an object that falls from a height of 39.6 meters. To determine this velocity, we can use the equation of motion for an object in free fall under the influence of gravity, assuming no air resistance. The equation is v = \(\sqrt{2gh}\), where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s2), and h is the height from which the object falls.
Plugging in the values, we get v = \(\sqrt{2 \times 9.81 \times 39.6}\). Calculating this gives us a final velocity v ≈ 27.9 m/s. Therefore, the object would strike the ground with a velocity of approximately 27.9 meters per second.
SUMUP of the final answer:\
- The equation used for calculation is v = \(\sqrt{2gh}\).
- The acceleration due to gravity (g) is taken as 9.81 m/s2.
- The final velocity (v) of the object is approximately 27.9 m/s.