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a rigid container has a mixture of carbon dioxide and krypton at 25oc. the mole fraction of the carbon dioxide is 0.600 and there are 254 g of krypton. calculate the total kinetic energy of the mixture.

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Final answer:

To calculate the total kinetic energy of a mixture of carbon dioxide and krypton in a rigid container at 25°C, one must utilize the kinetic molecular theory and the equipartition theorem, taking into account the mole fraction of CO2 and the mass and molar mass of krypton.

Step-by-step explanation:

The question presents a scenario of a rigid container with a mixture of carbon dioxide and krypton at 25°C. The mole fraction of carbon dioxide is 0.600, and there are 254 g of krypton. To calculate the total kinetic energy of the gas mixture, we need to apply concepts from kinetic molecular theory and the equipartition theorem.

Firstly, we will need to determine the number of moles of krypton, using its molar mass (83.798 g/mol). From there, we can find out the number of moles of carbon dioxide, given its mole fraction. We can then apply the equipartition theorem, which states that each mole of gas at a given temperature has the same average kinetic energy. The formula we use is (3/2)RT per mole, where R is the universal gas constant and T is the temperature in Kelvin.

Thus, the total kinetic energy of the gas mixture would be the sum of the kinetic energies of both gases, which can be found by multiplying the kinetic energy per mole by the number of moles for both carbon dioxide and krypton.

It's important to note that without the specific numerical values for R and a conversion of the temperature to Kelvin, we cannot provide a numerical result. The solution involves the calculation of moles, understanding the mole fraction, and application of the equipartition theorem in context of the kinetic theory of gases.

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