Final answer:
The minimum accelerating voltage required to produce an x-ray with a wavelength of 70.0 pm is 232,143 volts.
Step-by-step explanation:
To determine the minimum accelerating voltage required to produce an x-ray with a wavelength of 70.0 pm, we can use the equation relating the wavelength of x-rays to the accelerating voltage:
wavelength = h / (q * V)
Where wavelength is the wavelength of the x-ray, h is Planck's constant (6.626 x 10^-34 Js), q is the charge of the electron (1.602 x 10^-19 C), and V is the accelerating voltage.
Plugging in the known values, we have:
wavelength = (6.626 x 10^-34 Js) / (1.602 x 10^-19 C * V)
Solving for V:
V = (6.626 x 10^-34 Js) / (1.602 x 10^-37 C) / (70.0 x 10^-12 m)
V = 232,143 volts
Therefore, the minimum accelerating voltage required to produce an x-ray with a wavelength of 70.0 pm is 232,143 volts.