Final answer:
The actual number of protons giving rise to the signal at 1.1 ppm in a 1H NMR spectrum cannot be determined without the specific integration value for that signal. The integration value tells us the proportion of protons contributing to the signal, which corresponds to the number of protons in that chemical environment.
Step-by-step explanation:
Understanding 1H NMR Spectroscopy
In answering the question regarding the actual number of protons giving rise to the signal at 1.1 ppm in a 1H NMR spectrum for a compound with the molecular formula C₅H₁₀O, one must first understand how NMR (Nuclear Magnetic Resonance) spectroscopy works. The spectrum provides information about the different environments of hydrogen atoms (protons) in a molecule. Signals in the NMR spectrum correlate to protons in different chemical environments due to shielding or deshielding by surrounding electrons. The resonance frequency of these protons is reported in parts per million (ppm) relative to a standard reference compound, usually tetramethylsilane (TMS).
An integral part of analyzing NMR spectra is to use the integration values of each signal, which are proportional to the number of protons contributing to that signal. The signal at 1.1 ppm, which is in the region typical for methyl protons, would likely belong to a methyl group, and from the integration value presented, we can estimate how many protons give rise to that signal. Unfortunately, without the specific integration value provided in the question, we cannot give an exact number of protons at 1.1 ppm.
Overall, to determine the number of protons responsible for a particular signal in a 1H NMR spectrum, you would need to know the integration value associated with that signal. This integration value is a relative number that indicates how many protons are producing the signal when compared to the total number of protons in the sample.