61.7k views
2 votes
A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits into two parts with masses of 0.02 kg and 0.08 kg, respectively. Immediately after the separation, the 0.02 kg part moves horizontally due east. Air resistance is negligible. True statements about the 0.08 kg part include which of the following? i. It could move north immediately after the spring is released. II. It takes longer to reach the ground than does the 0.02 kg part. III. It strikes the ground farther from the launch point than does the 0.02 kg part. A) None B) I only C) Ill only D) I and II only E) II and III only

1 Answer

9 votes

Answer:

A

Step-by-step explanation:

Momentum conservation will cause 0.08kg to move to the west (opposite of 0.02 kg).

and because both are at the same height above the ground, they will take the same time to reach the ground.

The speed of 0.08kg will be less than 0.02 kg, let v be the speed of 0..02kg, then speed of 0.08kg V is

0.02v - (0.08)V = 0

V = 0.02 v/ 0.08 = v/4

The speed of 0.08 kg = v/4

The speed of 0.08 kg is less than 0.02kg.

So 0.02kg strikes the ground farther from the launch point than does the 0.08 kg

User Alex Beugnet
by
5.5k points