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approximately how much work is required to move a 2c (coulombs) point charge 2m in a 10v/m uniform electric field?

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Final answer:

Approximately 4 J of work is required to move a 2 c (coulombs) point charge 2 m in a 10 V/m uniform electric field.

Step-by-step explanation:

The work done to move a point charge in a uniform electric field can be calculated using the formula:



Work = force x distance



In this case, the force experienced by the point charge is given by:



Force = charge x electric field



Given that the charge is 2 c (coulombs) and the distance is 2 m, and the electric field is 10 V/m, we can substitute these values into the formula to find the work:



Work = (2 c) x (10 V/m) x (2 m) = 4 cV = 4 J



Therefore, approximately 4 J of work is required to move the 2 c point charge 2 m in a 10 V/m uniform electric field.

User Jeff Day
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