Question

Water has a very unique property. When liquid water freezes, it actually expands (i.e. its volume increases). You may have even seen a bottle of water or soda rupture when left in the freezer too long.

Imagine that you have 1040 kg of liquid water. What is the volume of this mass of water?
Vwater = ____________ m³

Answer 1

The volume of 1040 kg of water is 1.04 m³ at 0°C, given the density of water is about 1000 kg/m³. This expansion property of water upon freezing can exert significant force on containers.

Step-by-step explanation:

The calculation of the volume of water based on its mass can be performed using the concept of density. The density of water at 0°C is approximately 1000 kg/m³. To find the volume that 1040 kg of water occupies, we use the formula: Volume = Mass / Density. Thus, the volume of 1040 kg of water is 1040 kg / 1000 kg/m³ = 1.04 m³. This property of water is critical because when water freezes, it expands about 9%, leading to significant forces exerted on containers, potentially causing them to fracture.

The mass of the water is given as 1040 kg. To find the volume of water, we need to use the fact that the density of water is approximately 1000 kg/m³ at 0°C. Density is defined as mass divided by volume. So, density = mass / volume. Rearranging this equation, we get volume = mass / density.

Substituting the given values, volume = 1040 kg / 1000 kg/m³ = 1.04 m³. Therefore, the volume of 1040 kg of liquid water is 1.04 m³.