Answer:
Kindly check explanation
Explanation:
xbar = 2.6
Sample size, n = 100
s = 0.4
Mean, μ = 4
The test statistic :
(xbar - μ) ÷ s/sqrt(n)
(2.6 - 4) ÷ 0.4/sqrt(25)
1.4 ÷ 0.08
= −17.5
Critical tvalue for 95% confidence interval :
df = n - 1 = 25 - 1 = 24
Tcritical at 0.05/2; df
Tcritical = ±2.064
Since, Tstatistic value does not fall within the Tcritical value ±2.064, we reject the Null
Using the p value from Tstatistic calculator :
P value at t = - 17.5 at 0.05 < 0.000001
Since p value is < 0.05, we reject H0.