Final answer:
Using the balanced chemical equation, 0.80 moles of C₂H₂ will produce 0.80 moles of H₂O, as the molar ratio is 1:1, rounded to two significant figures.
Step-by-step explanation:
When calculating the amount of water (H₂O) produced in a chemical reaction, we reference the balanced chemical equation, which provides the molar ratios of reactants to products. In the equation 2C₂H₂ (g) + 5 O₂ (g) → 4CO₂ (g) + 2 H₂O (g), it indicates that for every 2 moles of acetylene (C₂H₂), 2 moles of water are formed. Therefore, if we have 0.80 moles of C₂H₂, we can use the mole ratio (2 moles C₂H₂ to 2 moles H₂O) to determine the moles of H₂O produced, which is simply a 1:1 ratio.
By setting up a proportion, we solve for the amount of H₂O produced:
- 2 moles C₂H₂ : 2 moles H₂O = 0.80 moles C₂H₂ : x moles H₂O
- x = 0.80 moles H₂O
Rounding our answer to two significant figures, we determine that 0.80 moles of C₂H₂ will produce 0.80 moles of H₂O.