Final answer:
To calculate the expected number of increasing subarrays of length k in a permutation of n distinct integers, one must consider the (n - k + 1) potential starting points and the probability 1/k! of each being increasing, resulting in an expectation of (n - k + 1) / k!.
Step-by-step explanation:
The question at hand requires the computation of the expected number of increasing subarrays of length k within a permutation of n distinct integers. To solve this problem, we need a combination of combinatorial mathematics and probability theory. Since the array contains a random permutation of integers, each element has an equal chance of being in an increasing subarray.
Considering the positions in the array, for a fixed k, there are (n - k + 1) possible starting points for a subarray of length k. Since every number is distinct and the permutation is random, the probability of any such subarray being increasing is 1/k! because there are k! possible orders for k numbers and only one of them is increasing.
Therefore, the expected number of increasing subarrays of length k is the product of the number of possible starting points and the probability of each being increasing, which turns out to be (n - k + 1) / k!.