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A barometer shows a 62.0 cm column of mercury. What is the external pressure in Pa, atm, torr, and mmHg? (g=9.81ms⁻² ; d(Hg)=13.6gcm⁻³)

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Final answer:

The external pressure caused by the column of mercury in a barometer can be calculated using the formula p = ρgh, where ρ is the density of mercury (13.6 g/cm³), g is the acceleration due to gravity (9.81 m/s²), and h is the height of the mercury column (0.62 m). The calculated external pressure is approximately 789.108 Pa, 5.918 mmHg, 5.918 torr, and 0.00666 atm.

Step-by-step explanation:

The external pressure caused by the column of mercury can be calculated using the formula:

p = ρgh

Where:

  • ρ is the density of mercury
  • g is the acceleration due to gravity
  • h is the height of the mercury column

Substituting the values into the formula, we have:

p = (13.6 g/cm³)(9.81 m/s²)(0.62 m)

Calculating this expression, the external pressure can be determined in Pascals (Pa). To convert this to other units commonly used, we have:

  • 1 Pa = 0.0075 mmHg
  • 1 Pa = 0.0075 torr
  • 1 Pa = 0.00000987 atm

Therefore, the external pressure is approximately 789.108 Pa, 5.918 mmHg, 5.918 torr, and 0.00666 atm.

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