Final answer:
Scientist B is correct because a test cross between a homozygous recessive parent and a heterozygous parent will result in a 1:1 phenotypic ratio of tall to short offspring, signifying a 50% tall and 50% short distribution.
Step-by-step explanation:
The correct scientist is Scientist B as they assert that a cross between a homozygous recessive parent and a heterozygous parent will result in offspring with a 50% tall phenotype and a 50% short phenotype. The option that fits this description is D.
This outcome is explained by a Punnett square, which predicts a 1:1 phenotypic ratio for such a cross, where T represents the dominant tall allele and t represents the recessive short allele.
In this cross (Tt x tt), the heterozygous (Tt) parent can provide a T (tall) or t (short) allele, while the homozygous recessive (tt) parent can only contribute a t (short) allele, resulting in half of the offspring being Tt (tall) and half being tt (short).
In this test cross, Scientist B is correct because one parent must be homozygous recessive while the other parent is heterozygous. When a homozygous recessive parent is crossed with a heterozygous parent, the resulting offspring will be 50% tall and 50% short. This is due to the inheritance pattern of a dominant-recessive trait.