Final answer:
To determine the mass percent of hydroxide, OH⁻, in Cu(H₂O)₄(OH)₂, calculate the mass of OH⁻ and divide it by the mass of Cu(H₂O)₄(OH)₂ and multiply by 100%.
Step-by-step explanation:
To determine the mass percent of hydroxide, OH⁻, in Cu(H₂O)₄(OH)₂, we need to know the molar mass of Cu(H₂O)₄(OH)₂ and the molar mass of the OH⁻ ion. The molar mass of Cu(H₂O)₄(OH)₂ is determined by adding the molar masses of copper, water, and hydroxide.
The molar mass of copper is 63.55 g/mol, the molar mass of water is 18.02 g/mol, and the molar mass of hydroxide is 17.01 g/mol. Therefore, the molar mass of Cu(H₂O)₄(OH)₂ is 63.55 + (18.02 × 4) + (17.01 × 2) = 245.13 g/mol.
To calculate the mass percent of OH⁻, we need to determine the mass of OH⁻ in Cu(H₂O)₄(OH)₂ and divide it by the mass of Cu(H₂O)₄(OH)₂, then multiply by 100. The mass of OH⁻ can be found by multiplying the number of OH⁻ ions in Cu(H₂O)₄(OH)₂ by the molar mass of OH⁻. In Cu(H₂O)₄(OH)₂, there are 2 OH⁻ ions. Therefore, the mass of OH⁻ is 2 × 17.01 = 34.02 g.
The mass percent of OH⁻ is calculated as (34.02 g / 245.13 g) × 100% = 13.88%. Therefore, the mass percent of OH⁻ in Cu(H₂O)₄(OH)₂ is approximately 13.88%.