Question

Hugo kicks the soccer ball at a speed of 5.0 m/s at an angle of 50°. How long was the ball in the air for?

A. 0.79s
B. 0.39s
C. 0.2s
D. 1.0s

Answer 1

To find the time the ball was in the air, we can use the equation t = 2*(v*sin(theta))/g, where v is the initial speed of the ball, theta is the launch angle, and g is the acceleration due to gravity. In this case, v = 5.0 m/s and theta = 50°. The ball was in the air for approximately 0.79 seconds.

Step-by-step explanation:

To find the time the ball was in the air, we can use the equation t = 2*(v*sin(theta))/g, where v is the initial speed of the ball, theta is the launch angle, and g is the acceleration due to gravity. In this case, v = 5.0 m/s and theta = 50°. We can use the equation to calculate t.

t = 2*(5.0*sin(50°))/9.8 = 0.79s

Therefore, the ball was in the air for approximately 0.79 seconds.

The correct option is A. 0.79s.