Answer: 0.27 moles of CO2 and 11.88 grams of CO2
Explanation: Use the Ideal Gas Law, PV = nRT, substitute the values given and solve.
I can't seem to upload procedure but:
P = 1.5atm
V = 4.5L
n = moles
R = 0.0821gr/mol (when using atm, kPa is 8.31)
T = 300K
Isolate what you don't have, in this case n. Change PV = nRT to PV/RT = n. Substitute the values to get moles. Once you have this, multiply the value by the molar mass of CO2 (44gr/mol) to get the mass of CO2 in grams.