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at 25°C, the vapor pressure of pure water is 0.0313 atm. what is the vapor pressure, in atm, when 28.1 g of nacl is dissolved in 100 g of water?

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Final answer:

To calculate the vapor pressure of a solution, use Raoult's Law. Convert the mass of NaCl to moles, calculate the mole fraction of water, and then multiply by the vapor pressure of pure water.

Step-by-step explanation:

To calculate the vapor pressure of a solution, you can use Raoult's Law. Raoult's Law states that the vapor pressure of a solvent above a solution is equal to the mole fraction of the solvent multiplied by its vapor pressure in its pure form. In this case, the solvent is water and the solute is NaCl.

First, convert the mass of NaCl to moles using its molar mass. Then, calculate the mole fraction of water by dividing the moles of water by the total moles of water and NaCl. Finally, multiply the mole fraction of water by the vapor pressure of pure water at the given temperature to find the vapor pressure of the solution.

For example, if the mole fraction of water is 0.9 and the vapor pressure of pure water at 25°C is 0.0313 atm, the vapor pressure of the solution would be 0.9 * 0.0313 = 0.02817 atm.

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