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write the chemical equation for dissociation of CH₃COOH in water, and describe why the solution containing methyl orange is of the color observed.

User Dice
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Final answer:

The chemical equation for the dissociation of CH₃COOH in water is CH₃COOH(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃COO⁻(aq). The color observed in a solution containing methyl orange is due to the equilibrium between the nonionized red form and the ionized yellow form of the indicator.

Step-by-step explanation:

The chemical equation for the dissociation of CH₃COOH (acetic acid) in water is:

CH₃COOH(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃COO⁻(aq)

This equation shows that acetic acid dissociates into hydronium ion (H₃O⁺) and acetate ion (CH₃COO⁻) in water. The reaction is reversible, indicating that it can go in both directions.

When a solution of methyl orange, an acid-base indicator, is added, it changes color in response to the equilibrium between the nonionized red form (HIn) and the ionized yellow form (In¯). Adding acid shifts the equilibrium towards the nonionized red form, while adding base shifts it towards the ionized yellow form. This behavior is in accordance with Le Chatelier's principle.

User Bill Noble
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