Final answer:
To determine the peak magnitude of the electric field from a given peak magnetic field of 17.5 nT in an EM wave, the equation E = cB is used, where c is the speed of light. Multiplying 17.5 nT by the speed of light yields a peak electric field magnitude of 525 mV/m.
Step-by-step explanation:
If the magnetic field in a traveling electromagnetic (EM) wave has a peak magnitude of 17.5 nT (nanoteslas), to calculate the peak magnitude of the electric field, we can use the relationship between the electric field (E) and the magnetic field (B) in an electromagnetic wave traveling in a vacuum. The relationship is given by the equation E = cB, where c is the speed of light in a vacuum, approximately 3.00 × 108 m/s.
To find the electric field, we multiply the peak magnetic field value by the speed of light:
E = c × B
E = 3.00 × 108 m/s × 17.5 × 10-9 T
E = 5.25 × 10-1 V/m
Therefore, the peak magnitude of the electric field associated with the given magnetic field is 525 mV/m (millivolts per meter)