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Tetrafluoroethylene, C₂F₄, can be converted to octafluorocyclobutane which can be used as a refrigerant or an aerosol propellant. A plot of 1/[C₂F₄] vs. time gives a straight line with a slope of 0.0448 L mol⁻¹s⁻¹. What is the rate law for this reaction? *show all work and calculations____

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Final answer:

The rate law for the reaction converting tetrafluoroethylene to octafluorocyclobutane follows second-order kinetics with the rate expression rate = 0.0448 [C₂F₄]².

Step-by-step explanation:

Rate Law for the Reaction

The conversion of tetrafluoroethylene (C₂F₄) to octafluorocyclobutane involves a reaction for which the kinetics can be studied by plotting 1/[C₂F₄] vs. time. A straight line obtained from this plot indicates that the reaction follows second-order kinetics.

To find the rate law, consider the rate expression for a general second-order reaction A → products: rate = k[A]². Given the slope of the line as 0.0448 L mol⁻¹s⁻¹, which represents the rate constant k, the rate law for this reaction can be written as rate = 0.0448 [C₂F₄]².

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