Question

a 2.0-cm-tall candle flame is 2.2 mfrom a wall. you happen to have a lens with a focal length of 32 cm .for each location, what is the height of the image? express your answers in centimeters and separated by a comma.

Answer 1

To calculate the height of the image produced by the lens at each location, use the lens formula. For the first location (2.2 m from the wall), the height of the image is 33.29 cm. For the second location (opposite side of the lens), the height of the image is -35.37 cm.

Step-by-step explanation:

To determine the height of the image produced by the lens, we can use the lens formula:

1/f = 1/v - 1/u

Where f is the focal length of the lens, v is the image distance, and u is the object distance. Given that the focal length of the lens is 32 cm, we need to calculate the image distance for each location.

For the first location, the object distance is 2.2 m = 220 cm. Plugging in the values into the lens formula, we get:

1/32 = 1/v - 1/220

Solving for v, we find:

v = 32 * 220 / (220 - 32) = 33.29 cm

Therefore, the height of the image at this location is 33.29 cm.

For the second location, the object distance is -2.2 m = -220 cm (negative sign indicates it is on the opposite side of the lens). Plugging in the values into the lens formula, we get:

1/32 = 1/v - 1/(-220)

Solving for v, we find:

v = 32 * (-220) / ((-220) + 32) = -35.37 cm

Therefore, the height of the image at this location is -35.37 cm.