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Upon being struck by 240 nm photons, a material ejects electrons with a maximum kinetic energy of what is the work function of this material?

O 3.43 eV
O 2.18 eV
O 2.60 eV
O 3.02 eV

User Ktyagi
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Final answer:

The work function of a material can be found by using the photoelectric effect equation, but without a correct maximum kinetic energy value matching the provided options, we cannot identify the correct work function from the available choices.

Step-by-step explanation:

The question is asking to determine the work function of a material that ejects electrons when struck by photons with a wavelength of 240 nm. The work function can be found using the equation for the photoelectric effect, which is KEmax = hf - φ, where KEmax is the maximum kinetic energy of the photoelectrons, hf is the energy of the incident photons, and φ (phi) is the work function of the material.

First, we calculate the energy of the incident photons (hf) using the equation hf = hc/λ, where h is Planck's constant (4.135667696 × 10-15 eV·s), c is the speed of light (approximately 3 × 108 m/s), and λ is the wavelength of the incident light in meters (240 nm = 240 × 10-9 m). Substituting the values into the equation, we find hf = (4.135667696 × 10-15 eV·s) × (3 × 108 m/s) / (240 × 10-9 m), which gives hf = 5.18 eV.

Since the maximum kinetic energy (KEmax) is given, we can rearrange the photoelectric effect equation to find the work function (φ). That is, φ = hf - KEmax. We can then plug in the values hf = 5.18 eV and KEmax = 3.43 eV (correct option) to find φ = 5.18 eV - 3.43 eV = 1.75 eV. However, this value does not match any of the options provided in the question, so there may be a mistake in the given information.

Therefore, without additional information or clarification on the maximum kinetic energy of the ejected electrons or the provided options, it is not possible to confidently select the correct option.

User TimGJ
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