Final answer:
To prepare 100 mL of a 3 M Nitric acid solution from a 15 M stock solution, 20 mL of the stock solution is needed to be diluted with water to the desired volume.
Step-by-step explanation:
The student's question revolves around preparing a solution of a specific molarity using a stock solution. The fundamental concept here is the dilution of solutions. The method to calculate the volume required from the stock solution uses the formula: M1V1 = M2V2, where M1 and V1 are the molarity and volume of the stock solution, and M2 and V2 are the molarity and volume of the desired solution.
Based on the given question, and ignoring the typos and irrelevant parts, the student wants to prepare 100 mL (0.1 L) of a 3 M Nitric acid solution using a stock solution of 15 M. Using the dilution formula, we calculate the volume of the stock solution needed:
V1 = (M2 x V2) / M1
V1 = (3 M x 0.1 L) / 15 M = 0.02 L
Therefore, the volume of the 15 M Nitric acid needed is 20 mL, which can be measured using a pipette or burette.
The second part of the question seems to be misplaced, as it deals with preparing a nitric acid solution, not a base like NH3(aq). So, we'll focus only on the preparation of nitric acid.