Question

The density of butanol, C4H10O, is 0.810 g/mL. How many moles of butanol are present in 1.00 liters of butanol?

a) 0.0915 moles
b) 1.67 x 10⁻⁵ moles
c) 10.9 moles
d) 6.00 x 10⁻⁴ moles
e) 0.0600 moles

Answer 1

To calculate the number of moles of butanol in 1.00 liter, first convert the volume to milliliters (1000 mL), then calculate the mass using the density (0.810 g/mL) and finally divide mass by the molar mass of butanol (74.12 g/mol), resulting in 10.9 moles.

Step-by-step explanation:

To find the number of moles of butanol in 1.00 liters of butanol, we need to use the density of butanol which is 0.810 g/mL. First, we should convert the volume from liters to milliliters because the density is given in grams per milliliter. There are 1000 milliliters in one liter, so 1.00 liter is equal to 1000 milliliters.

Next, we calculate the mass of butanol using the formula: density = mass/volume. Rearranging the formula, we get mass = density × volume. Plugging in the numbers, we get mass = 0.810 g/mL × 1000 mL = 810 grams of butanol.

Now, we need the molar mass of butanol. Butanol (C4H9OH) has a molar mass of approximately 74.12 g/mol. To find the number of moles, we divide the mass by the molar mass: moles = mass/molar mass. So, we have moles = 810 g / 74.12 g/mol, which equals approximately 10.9 moles.

Therefore, the correct answer is c) 10.9 moles of butanol are present in 1.00 liter of butanol.