Question

The center of gravity of a uniform meter stick weighing 150.0 g needs to be shifted to 40.0 cm mark by gluing an additional mass at the 10.00 cm mark. Calculate the required mass?

Answer 1

To shift the center of gravity of a meter stick to the 40.0 cm mark, a mass of 62.5 g needs to be glued at the 10.00 cm mark.

Step-by-step explanation:

To shift the center of gravity of the meter stick to the 40.0 cm mark, we need to calculate the required mass to be glued at the 10.00 cm mark. The center of gravity of the meter stick can be found using the formula:

x₁m₁ + x₂m₂ = x₃m₃

Where x is the distance from the fulcrum and m is the mass. In this case, we have:

(0.100 m)(150.0 g) + (0.300 m)(m) = (0.400 m)(m)

Solving for m, we get:

m = 62.5 g

Therefore, a mass of 62.5 g needs to be glued at the 10.00 cm mark to shift the center of gravity to the 40.0 cm mark.