Final answer:
To balance the redox reaction Pb(s) + NO3-(aq) → Pb2+(aq) + NO(g) using the half-reaction method, the balanced equation in acidic solution is 3Pb(s) + 2NO3-(aq) + 8H+(aq) → 3Pb2+(aq) + 2NO(g) + 4H2O(l).
Step-by-step explanation:
The question asks to use the half-reaction method to balance the redox reaction between lead (Pb) and nitrate ions (NO3-) in an acidic solution, resulting in Pb2+ and nitrogen monoxide (NO).
To do this, we will separate the reaction into two half-reactions - one for oxidation and one for reduction - and then balance each one before combining them for the overall balanced equation.
Oxidation Half-Reaction:
Pb(s) → Pb2+(aq) + 2e-
Reduction Half-Reaction:
NO3-(aq) + 4H+(aq) + 3e- → NO(g) + 2H2O(l)
Combined Balanced Reaction:
3Pb(s) + 2NO3-(aq) + 8H+(aq) → 3Pb2+(aq) + 2NO(g) + 4H2O(l)