Question

Collin stands on a 60.0 m high cliff shooting a cannon. He is using a launch angle of 42.0 degree and his cannon launches the cannon balls at 25.0 m/s.

Where does it land?
(a) 104 m (b) 98.8 m (c) 112 m (d) 108 m (e) None of the above

Answer 1

The cannonball will land 98.8 m away from the cliff. Therefore, the answer is (b) 98.8 m.

Step-by-step explanation:

To find where the cannonball lands, we can analyze the vertical and horizontal components of its motion separately.

For the horizontal motion, we can use the formula:

horizontal distance = velocity * time

Since the angle is above the horizontal, the initial velocity is 25 m/s * cos(42). The time it takes to reach the ground can be found using the formula:

time = vertical velocity / g

where g is the acceleration due to gravity. Then, we can calculate the horizontal distance by multiplying the time by the horizontal velocity.

The cannonball will land 98.8 m away from the cliff. Therefore, the answer is (b) 98.8 m.