Final answer:
The frequency of a photon produced in a CRT with a 25.0-kV accelerating potential is approximately 9.614 x 10^15 Hz.
This correct answer is none of the above.
Step-by-step explanation:
The frequency of a photon produced in a CRT using a 25.0-kV accelerating potential can be determined using the formula:
f = eV/h
Where:
- f is the frequency of the photon
- e is the elementary charge (1.602 x 10^-19 C)
- V is the accelerating potential (25,000 V)
- h is Planck's constant (6.63 x 10^-34 J·s)
Substituting the values into the formula:
f = (1.602 x 10^-19 C) x (25,000 V) / (6.63 x 10^-34 J·s)
f ≈ 9.614 x 10^15 Hz
This correct answer is none of the above.
Your correct question is: Cineradiography framing frequencies above _ frames/sec are typically only necessary for recording pediatric coronary angiography.
1. 60
2. 30
3. 90
4. 15