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Normally, which size of image intensifier unit will produces the best overall image quality?

1. 9"
2. 6"/9"
3. 6"/ 9"/12"
4. quadruple mode unit

1 Answer

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Final answer:

The power output of the imaging device is calculated by multiplying the intensity (1.50×10² W/m²) by the area (0.0015 m²) resulting in a power output of 0.225 Watts.

Step-by-step explanation:

To calculate the power output of the medical imaging device, we start by using the formula for power (P), which is the product of the intensity (I) and the area (A) over which the intensity is distributed. The device has been described as having an intensity of 1.50×10² W/m² and a rectangular head measuring 3.00 by 5.00 cm. First, we convert the dimensions of the head from cm to m: 3.00 cm = 0.03 m and 5.00 cm = 0.05 m. The area is thus 0.03 m * 0.05 m = 0.0015 m². We then multiply the intensity by the area to get the power output: 1.50×10² W/m² * 0.0015 m² = 0.225 W.

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