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Normally, which size of image intensifier unit will produce the best overall image quality?

1. 9"
2. quadruple mode unit
3. 6"/9"12'
4. 6"/9"

User Mpapec
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1 Answer

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Final answer:

To calculate the power output, multiply the ultrasound intensity by the converted area of the device head, resulting in a power output of 0.225 W.

Step-by-step explanation:

To find the power output of a medical imaging device, we use the formula Power (P) = Intensity (I) × Area (A). Given the ultrasound intensity is 1.50×10² W/m² and the head of the device measures 3.00 cm by 5.00 cm, we must first convert the measurements from centimeters to meters (0.03 m × 0.05 m). Now calculate the area A = 0.03 m × 0.05 m = 0.0015 m². Multiply the intensity by the area to find the power: P = 1.50×10² W/m² × 0.0015 m² results in P = 0.225 W, which is the power output of the imaging device.

User Lillieth
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