19.3k views
5 votes
Solve the system of linear equations by elimination. Check your solution x+2y=13 -x+y=5

2 Answers

5 votes

Answer:

To solve the system of linear equations by elimination, let's add the two equations to eliminate one of the variables:

x + 2y = 13 (Equation 1)

-x + y = 5 (Equation 2)

Adding the two equations,

(x + 2y) + (-x + y) = 13 + 5

This simplifies to:

3y = 18

y = 18/3

y = 6

Substitute value of y into one of the equations, let's use Equation 2,

-x + 6 = 5

-x = 5 - 6

-x = -1

x = 1

So, the solution to the system of linear equations is x = 1 and y = 6.

User Alexpanter
by
7.9k points
4 votes

Final answer:

The linear equations x+2y=13 and -x+y=5 are solved by elimination to get x=1 and y=6, which is verified by substituting these values back into the original equations.

Step-by-step explanation:

To solve the system of linear equations by elimination, we start with the given equations:

  1. x + 2y = 13
  2. -x + y = 5

Now, we will add the two equations together to eliminate the variable x:

(x - x) + (2y + y) = 13 + 5

This simplifies to:

0x + 3y = 18

With only one variable remaining, y, we can now solve for y:

y = 18 / 3

y = 6

To find the value of x, we substitute y=6 back into either one of the original equations. We'll use the second equation (-x + y = 5):

-x + 6 = 5

-x = -1

x = 1

Therefore, the solution to the system is x = 1 and y = 6.

User Facundo Olano
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories