Question

How many moles of SnO2 would need in order to produce 8.67 moles of Sn?

Answer 1

To produce 8.67 moles of Sn, you would need 8.67 moles of SnO2. The balanced equation indicates a 1:1 mole ratio between SnO2 and Sn.

Step-by-step explanation:

To determine how many moles of SnO2 are needed to produce 8.67 moles of Sn, we must consider the stoichiometry of the reaction. The balanced equation for converting tin(IV) oxide (SnO2) to tin (Sn) is

SnO2 (s) → Sn (s) + O2 (g)

From the balanced equation, it is clear that 1 mole of SnO2 produces 1 mole of Sn. Therefore, to produce 8.67 moles of Sn, you would need 8.67 moles of SnO2.

Addressing some other aspects:

1. If you multiply grams of Sn by 118.69 grams/mole Sn, you convert the mass of Sn to moles.
2. A balanced equation is needed to understand the mole ratio between reactants and products.
3. The physical form of the material does not alter the stoichiometric calculations; however, it may be important for the actual chemical reaction process.

Answer 2

8.67 mol SnO₂

Step-by-step explanation:

Step 1: Write the balanced equation for the decomposition reaction of SnO₂ to produce Sn

SnO₂(s) ⇒ Sn(s) + O₂(g)

Step 2: Establish the appropiate molar ratio

According to the balanced equation, the molar ratio of SnO₂ to Sn is 1:1.

Step 3: Calculate the moles of SnO₂ required to produce 8.67 moles of Sn

We will use the established molar ratio.

8.67 mol Sn × 1 mol SnO₂/1 mol sn = 8.67 mol SnO₂