Question

Given matrices A and B shown below, find (−2)A+(−1)B.

Answer 1

Multiply each element of A by -2, each of B by 8. Add corresponding elements. Result:
`\((-2)A + (8)B = \begin{bmatrix} -64 & 20 \\ -28 & -20 \end{bmatrix}\).`

To find (-2)A + (8)B, first, multiply each element of matrix A by (-2) and each element of matrix B by 8. Then, add the corresponding elements of the resulting matrices.

Matrix A:

`\[ A = \begin{bmatrix} -24 & -30 \\ -2 & -2 \end{bmatrix} \]`

Matrix B:

`\[ B = \begin{bmatrix} -14 & -5 \\ -4 & -3 \end{bmatrix} \]`

Multiply each element of A by (-2):

`\[ (-2)A = \begin{bmatrix} 48 & 60 \\ 4 & 4 \end{bmatrix} \]`

Multiply each element of B by 8:

`\[ (8)B = \begin{bmatrix} -112 & -40 \\ -32 & -24 \end{bmatrix} \]`

Now, add the corresponding elements:

`\[ (-2)A + (8)B = \begin{bmatrix} 48 - 112 & 60 - 40 \\ 4 - 32 & 4 - 24 \end{bmatrix} = \begin{bmatrix} -64 & 20 \\ -28 & -20 \end{bmatrix} \]`

Therefore,
`\((-2)A + (8)B = \begin{bmatrix} -64 & 20 \\ -28 & -20 \end{bmatrix}\).`

Que. Given matrices A and B shown below, find
(−2)A+(8)B. A=[−24−30−2−2] and B=[−145−4−5−3] find matrix