Question

What is the mass percent of methanol in a solution prepared by adding 32.0g of methanol to 18.0 grams of water?

Answer 1

The mass percent of methanol in the solution is calculated by dividing the mass of methanol by the total mass of the solution and multiplying by 100. For 32.0g of methanol and 18.0g of water, the mass percent of methanol is 64.0%.

Step-by-step explanation:

The mass percent of methanol in the solution is calculated by taking the mass of the methanol and dividing it by the total mass of the solution, then multiplying by 100 to convert it to a percentage. The question wrongly references ethanol, but the student is asking about methanol, so we will provide the correct calculation.

First, we need to find the total mass of the solution, which is the sum of the mass of methanol and the mass of water. This gives us 32.0 g (methanol) + 18.0 g (water) = 50.0 g (total mass of solution).

The mass percent of methanol is then: (32.0 g / 50.0 g) × 100 = 64.0%.