Question

A 2. 26 l balloon of helium is at 30°c and 1. 61 atm, what is the pressure if the volume is increased to 4. 12 l?.

Answer 1

`P_2=0.636atm`

Step-by-step explanation:

According to Boyle's Law:

`P_1V_1=P_2V_2\\P_1=1.61atm\\V_1=2.26L\\V_2=4.12L\\P_2=(P_1V_1)/(V_2)\\P_2=((1.61atm)(2.26L))/(4.12L)\\P_2=0.636atm`

This makes sense because according to Boyle's Law, the volume of a given amount of gas at a constant temperature is inversely proportional to its pressure. As the volume increases, the pressure must decrease proportionately.