Final answer:
The molarity of ethanol in the 2.00-liter solution is calculated by dividing the number of moles of ethanol, which is determined using its molar mass and the given mass, by the volume of solution, yielding a result of 0.1248 M.
Step-by-step explanation:
To calculate the molarity of ethanol in the solution, we need to use the formula: molarity = moles of solute / liters of solution. First, we find the moles of ethanol by using its molar mass. The molar mass of ethanol (C2H5OH) is approximately 46.07 g/mol.
To find the moles of ethanol in 11.5 grams of ethanol, the calculation is as follows:
- Moles of ethanol = mass of ethanol / molar mass of ethanol
- Moles of ethanol = 11.5 g / 46.07 g/mol
- Moles of ethanol = 0.2496 mol (rounded to four decimal places)
Next, we can find the molarity by dividing the moles of ethanol by the volume of the solution in liters:
- Molarity = moles of ethanol / volume of solution
- Molarity = 0.2496 mol / 2.00 L
- Molarity = 0.1248 M (rounded to four decimal places)
Therefore, the molarity of ethanol in the 2.00 liter solution is 0.1248 M.